Math 1101
Final Review
Fall 2002
Solutions (not guaranteed)
|
Number of Voters |
12 |
21 |
8 |
10 |
2 |
|
1st Choice |
B |
A |
D |
C |
A |
|
2nd Choice |
D |
D |
C |
A |
C |
|
3rd Choice |
A |
C |
A |
D |
D |
|
4th Choice |
C |
B |
B |
B |
B |
i. A has 23 1st place votes and wins
i. A 162, B 89, C 124, D 155: A wins
i. A defeats B, A defeats C, A defeats D and A is the winner.
i. D is the first eliminated as they have a mere 8 votes, C gets 8 more fist place votes and B is eliminated. This then give A 35 first place votes and A is the winner.
i. B has 12 first place votes and comes in second.
i. A won, so we remove A from the list. Now B has 77 points, C has 106 points, D has 135 points and D comes in second.
A is the Condorcet Candidate as they defeat everyone in head to head competition.
Weighted Voting:
i. Winning coalitions
Coalition critical members
P1,p2 p1, p2
P1, p3 p1, p3
P1,p2, p3 p1
P1, p2, p4 p1, p2
P1,p2, p5 p1, p2
P1,p3,p4 p1,p2
P1,p3,p5 p1,p3
P1,p4,p5 p1, p4, p5
P2,p3,p4 2,3,4
P2,p3,p5 2,3,5
P1.p2,p3,p4 none
P1.p2,p3,p5 none
P1.p2,p4,p5 p1
P1.p3,p4,p5 p1
P2,p3,p4,p5 1,2
P1,p2,p3,p4,p5 None
Player number times critical Power index
P1 11 11/26
P2 7 7/26
P3 4 4/26
P4 2 2/26
P5 2 2/26
i. Let x = the value of the strawberry portion, then
5x = the value of the chocolate portion
The total value of the cake is x + 5x = 24
X = $4
The chocolate portion is worth $20.
The Bids are:
|
|
Mavis |
Donald |
Douglas |
|
Car |
15000 |
10,000 |
5,000 |
|
Yacht |
15,000 |
25,000 |
20,000 |
|
Jewelry |
10,000 |
5,000 |
18,000 |
|
Total Value |
40,000 |
40,000 |
43,000 |
|
Should get |
13,333.33 |
13,333.33 |
14,333.33 |
Car: Mavis
Yacht: Donald
Jewelry: Douglas
Mavis gets car and pays 1,666.67 to the pot.
Donald gets the yacht and pays 11,666.67 to the pot
Douglas gets the Jewelry and pays 3,666.67 to the pot.
The pot has $17000.01 in it. This is divided out three ways and each person gets $5666.67
Mavis gets car and gets $4000.
Donald gets the yacht and pays $6,000
Douglas gets the Jewelry and gets $2000.
Apportionment:
|
|
Population In ten
thousands |
Lower Quota |
Standard Quota |
Upper Quota |
Apportionment Hamil? Jeff |
|
|
Minnesota |
492 |
27 |
27.94 |
28 |
28 |
|
|
Wisconsin |
536 |
30 |
30.44 |
31 |
30 |
|
|
Iowa |
293 |
16 |
16.64 |
17 |
17 |
|
|
Kansas |
269 |
15 |
15.28 |
16 |
15 |
|
|
Nebraska |
171 |
9 |
9.71 |
10 |
10 |
|
|
Total |
1761 |
97 |
|
102 |
|
|
|
|
Population |
Lower Quota |
Modified Quota |
Upper Quota |
Apportionment |
|
In ten
thousands |
Jeff |
||||
|
Minnesota |
492 |
28 |
28.63714 |
29 |
28 |
|
Wisconsin |
536 |
31 |
31.19818 |
32 |
31 |
|
Iowa |
293 |
17 |
17.05423 |
18 |
17 |
|
Kansas |
269 |
15 |
15.6573 |
16 |
15 |
|
Nebraska |
171 |
9 |
9.953152 |
10 |
9 |
|
|
17.18049 |
100 |
|
105 |
|
|
|
Population |
Lower Quota |
modified Quota |
Upper Quota |
Apportionment |
|
In ten
thousands |
Adams |
||||
|
Minnesota |
492 |
27 |
27.3799 |
28 |
|
|
Wisconsin |
536 |
29 |
29.82851 |
30 |
|
|
Iowa |
293 |
16 |
16.30551 |
17 |
|
|
Kansas |
269 |
14 |
14.9699 |
15 |
|
|
Nebraska |
171 |
9 |
9.516184 |
10 |
|
|
|
17.96939 |
95 |
|
100 |
|
|
|
Population |
Lower Quota |
Standard Quota |
Upper Quota |
Apportionment |
|
In ten
thousands |
Webster’s |
||||
|
Minnesota |
492 |
27 |
27.93867 |
28 |
28 |
|
Wisconsin |
536 |
30 |
30.43725 |
31 |
30 |
|
Iowa |
293 |
16 |
16.63827 |
17 |
17 |
|
Kansas |
269 |
15 |
15.27541 |
16 |
15 |
|
Nebraska |
171 |
9 |
9.710392 |
10 |
10 |
|
|
17.61 |
97 |
|
102 |
100 |
Use the following algorithms to find a path for a traveling salesman visiting each of the following cities:
|
|
Alexandria |
Minneapolis |
Rochester |
Brainerd |
Bemidji |
Mankato |
|
Alexandria |
* |
131 |
214 |
86 |
133 |
165 |
|
Minneapolis |
131 |
* |
83 |
125 |
214 |
120 |
|
Rochester |
214 |
83 |
* |
208 |
297 |
83 |
|
Brainerd |
86 |
125 |
208 |
* |
97 |
179 |
|
Bemidji |
133 |
214 |
297 |
97 |
* |
266 |
|
Mankato |
165 |
120 |
83 |
179 |
266 |
* |
|
Task |
Length of Task |
Tasks that must be completed Before you can start |
|
A |
7 |
|
|
B |
5 |
|
|
C |
6 |
|
|
D |
8 |
|
|
E |
5 |
A ,B |
|
F |
7 |
E, C |
|
G |
5 |
D, F |
|
H |
4 |
E |
|
I |
4 |
F |
|
J |
3 |
G,I |
|
K |
1 |
H, L |
|
L |
4 |
I |
|
M |
3 |
L, J |
|
N |
6 |
K |
|
O |
3 |
L |
= 55
One Payment: Compound interest. Looking for a future value

One Payment: Compound interest looking for a present value.

Future Value of an annuity due.
Let’s think of this as two annuities. One worth $200 going from 1/1/03 to 12/1/39 and another worth $300 starting 1/1/14 and last payment on 12/2/39. Then add the two annuities together.


This is the present value of an ordinary annuity to find the payment.
![]()
R=1018.18